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Use Diner and Restaurant Math to calculate your age

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Old 04-24-2007, 06:52 PM
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I know there's a mathematical trick here but it's still pretty interesting...

YOUR AGE -- BY EATING OUT

Don't tell me your age; you probably would tell a falsehood anyway-but your waiter may know!

YOUR AGE BY DINER & RESTAURANT MATH

This is pretty neat.

DON'T CHEAT BY SCROLLING DOWN FIRST!
It takes less than a minute. Work this out as you read...
Be sure you don't read the bottom until you've worked it out!
This is not one of those waste of time things, it's fun.

1. First of all, pick the number of times a week that you would like to go out to eat.
(more than once but less than 10)

2. Multiply this number by 2 (just to be bold)

3. Add 5

4. Multiply it by 50

5. If you have already had your birthday this year add 1757...
If you haven't, add 1756.

6. Now subtract the four digit year that you were born.

You should have a three digit number

The first digit of this was your original number. (I.e., How many times you
want to go out to restaurants in a week.)

The next two numbers are

YOUR AGE ! ------ (Oh YES, it is!!!)
Old 04-24-2007, 09:10 PM
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it worked... niiiiiice
Old 04-25-2007, 12:06 AM
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The wonders of math !
Old 04-25-2007, 02:26 AM
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wow indeed it worked
Old 04-25-2007, 08:53 AM
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or we could say...

(x*2+5)50+1756-y=100x+2006-y

(2x+5)50+1756-y=100x+2006-y

100x+250+1756-y=100x+2006-y

100x+2006-y=100x+2006-y

x+2006-y=x+2006-y

x-y=x-y

...all of these word games can be broken down to simple math, and then just canceled out.

Old 05-09-2007, 12:17 AM
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Originally Posted by tjleeland' post='417701' date='Apr 26 2007, 12:53 AM
or we could say...

(x*2+5)50+1756-y=100x+2006-y

(2x+5)50+1756-y=100x+2006-y

100x+250+1756-y=100x+2006-y

100x+2006-y=100x+2006-y

x+2006-y=x+2006-y

x-y=x-y

...all of these word games can be broken down to simple math, and then just canceled out.

you actually went thur the process of proving it
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